(H)0canbewrittenas__________in p by p v form.
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Answer:
Given equation:
5
x
2
−
3
=
10
x
Subtract
10
x
from both sides of the above equation.
5
x
2
−
3
−
10
x
=
10
x
−
10
x
5
x
2
−
10
x
−
3
=
0
Comparing the obtained equation with quadratic equation
a
x
2
+
b
x
+
c
=
0
, we have:
a
=
5
b
=
−
10
c
=
−
3
Substitute all the obtained values in the quadratic formula.
x
=
−
b
±
√
b
2
−
4
a
c
2
a
=
−
(
−
10
)
±
√
(
−
10
)
2
−
4
(
5
)
(
−
3
)
2
(
5
)
=
10
±
√
100
+
60
10
=
10
±
√
160
10
=
10
±
4
√
10
10
=
10
+
4
√
10
10
,
10
−
4
√
10
10
=
2
(
5
+
2
√
10
)
10
,
2
(
5
−
2
√
10
)
10
=
5
+
2
√
10
5
,
5
−
2
√
10
5
Thus, the solution of the quadratic equation is
x
=
5
+
2
√
10
5
,
5
−
2
√
10
5
.
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