Question

H^2 = B^2 + P^2. find h when B =5m and P =12m​

Answer 1

Answer:

$h = \sqrt{ {5}^{2} + {12}^{2} } = \sqrt{25 + 144 }= \sqrt{169} =13$

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Answer 2

Answer:

Step-by-step explanation:

Given:

B=5 m,

P= 12 m,

H²=B²+P²,

H²=12²+5²,

H²=144+25,

H²=169,

H=√169,

H=13.

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