Question

(h) 3s = 0 (1) 2q + 6 = 12​

Answer 1

$\huge\red{Answer:-}$

(i) $3s=0$

⇒$s=\frac{0}{3}$

⇒$s=0$

(ii) $2q+6=12$

⇒$2q=12-6$

⇒$2q=6$

⇒$q=\frac{6}{2}$

⇒$q=3$

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