Question

(H+) = 4.912 × 10 power -5 find ph​

Answer 1

Answer:

Explanation:

[$H^{+}$]=4.912*10^-5

$p^{h}$=log[$H^{+}$]

   =log[4.912*10^-5]

    =3.3087

Answer 2

Answer:

   =3.3087

Explanation:

[H^{+}]=4.912*10^-5

p^{h}=log[H^{+}]

  =log[4.912*10^-5]

   =3.3087