Physics, asked by godniladri, 3 months ago

`h A ball descended along a smooth curve of vertical height h and vertical circular path with radius r velocity according to the total circumference Achieved. Show that the ball will cross the circle if h>5r/2​

Answers

Answered by s1243amishi9836
1

Answer:

PHYSICS

A ball is released from height along the slope and move along a circular track of radius R without falling vertically downwards Show that h=

2

5

ANSWER

As the ball is released from a height and moves along a circular track it has sufficient velocity at the lowest point to loop a loop.

At lowest point v=

5gR

Using energy conservation

mgh=

2

1

×5gR

h=

2

5

R

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