`h A ball descended along a smooth curve of vertical height h and vertical circular path with radius r velocity according to the total circumference Achieved. Show that the ball will cross the circle if h>5r/2
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Answer:
PHYSICS
A ball is released from height along the slope and move along a circular track of radius R without falling vertically downwards Show that h=
2
5
ANSWER
As the ball is released from a height and moves along a circular track it has sufficient velocity at the lowest point to loop a loop.
At lowest point v=
5gR
Using energy conservation
mgh=
2
1
×5gR
h=
2
5
R
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