Question

∆H and ∆S for for the reaction
Ag2O(s) -----------> 2Ag(s) +1/2O2(g)..
35.56 kJ /mol and 67.0 J/k/mol respectively.calculate the temperature at which the free energy change for the reaction will be zero.​

Answer 1

Answer:

According to Gibbs Hamholtz equation..

∆G = ∆H - T ∆S

at equilibrium...

∆G = 0....So That......

0 = ∆H - T ∆S... (or)..∆H = T∆S

or....

T = ∆H/∆S

Here...

∆H = 13.56 kJ Mol^-1

= 30560 KJ mol^-1

∆S = 66.0Jk ^-1 mol^-1

So..

T = 30560 / 67 = 456 k..

Answer 2

Explanation:

Refer to the attachment

Thermodynamics class 11

Good question