Question

H-atom is exposed to electromagnetic radiation of wavelength 1028Åand gives out induced radiations.Calculate wavelength of these radiations.
Plz explain the concept of induced radiations.

SHAR

​

Answer 1

Explanation:

Induced radioactivity will occur when a stable matter is exposed to radioactive rays of specific electromagnetic radiations. In the given case, a hydrogen atom will become radioactive by exposing to electromagnetic radiation of λ of 1028 Angstrom.  

1 J = 6.24 e 18 electron volts

1.93 e -18 J = ( 6.24 e 18 * 1.93 e -18 ) = 12.06 electron volts

The ground state energy of hydrogen atom will be 13.6 electron volts.

E1 - E2 = 13.6 - ( 13.6 / n^2 ) = 13.6 - ( 13.6 / 2^2 ) = 13.6 - 3.4 = 10.2 electron volts

E1 - E3 = 13.6 - ( 13.6 / n^2 ) = 13.6 - ( 13.6 / 3^2 ) = 13.6 - 1.51 = 12.08 electron volts

λ1 = n 3----> 1

λ2 = n 3----> 2

λ3 = n 2----> 1

λ = hc / ΔE

λ1 = hc / E1 - E3 = 6.626 e-34   x 3 e8 / ( 13.6 - 1.51 ) x 1.6 e-19 = 1027 Angstrom

λ2 = hc / E2 - E3 = 6.626 e-34   x 3 e8 / ( 3.4 - 1.51 ) x 1.6 e-19 = 6573 Angstrom

λ3 = hc / E1 - E2 = 6.626 e-34   x 3 e8 / ( 13.6 - 3.4 ) x 1.6 e-19 = 1218 Angstrom