Math, asked by rajhritik36, 1 year ago

h by 4 =tanx
h by 9=cot
Find the value of h by putting the value in h.
Answer=6

Answers

Answered by sumanta28
0

here, h/4=tanx

we know , cotx =1/tanx

=1/h/4 =4/h.......1

cotx= 4/ h

tanx= 1/ cotx

= 1/4/h

h/4..... .ii

we get from i and ii

4/h=h/4


rajhritik36: wrong
rajhritik36: Answer is 6
Answered by noisyboy1001
2

Answer:

Step-by-step explanation:

tan x=H/4

cot  x=H/9

4 tan x=H...... (1)

Similarly 9 cot x=H..... (2)

Then , 4 tan x=9 cot x

4 tan x=9 1/tan x (cot x=1/tan x)

4 tan x*tan x=9

4 tan^2 x=9

tan^2 x=9/4

tan x=underoot 9/4

tan x=3/2..... (3)

Sub (3) in (1) and (2)

4*3/2=6

9*1/(3/2)=9*2/3=6

HENCE PROVED. ...

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