Question

H.C.F. AND L. C. M. OF TWO NUMBERS IS 9 AND 270 RESPECTIVELY. IF ONE OF THE TWO NUMBER IS 54. [ FIND THE OTHER NUMBER ]​

Answer 1

Answer:

45

Step-by-step explanation:

Before solving this question, you should know one important rule--->

HCF X LCM = PRODUCT OF THE NUMBERS

Now, it can be easily solved by substituting the given values.

9 x 270 = 54 x N  [where N is the other number]

N = 9 x 270 / 54

N = 45

Hope it helps :)

Answer 2

Answer :-

• The required number is 45.

Step-by-step explanation ::

To Find :-

• The other number

Solution :-

Given that,

• The H.C.F and L.C.M of two numbers are 9 and 270
• One of the numbers is 54

As we know that,

First number × Second number = H.C.F × L.C.M,

Assumption: Let us assume the second number as x,

Therefore,

• 54 × x = 9 × 270

=> 54 × x = 9 × 270

=> x = { 9 × 270 } ÷ { 54 }

Dividing 9 and 54 with 9

=> x = { 1 × 270 } ÷ { 6 }

Dividing 270 and 6 with 3

=> x = { 90 } ÷ { 2 }

Dividing 90 and 2 with 2

=> x = 45

Therefore, the value of x is 45.

As we assumed the second number as x, So,

=> Second number [ x ]

=> 45

Hence, the second Number is 45.

Now, Verification

• 54 × x = 9 × 270

We have,

• L.H.S = First number × Second number [ 54 × x ]
• R.H.S = H.C.F × L.C.M [ 9 × 270 ]

By evaluating L.H.S and R.H.S, putting the value of x

• L.H.S

=> 54 × x

=> 54 × 45

=> 2430

• R.H.S

=> 9 × 270

=> 2430

Hence, L.H.S = R.H.S

Hence, Verified!