Question

H.C.F of 16(a^4)(b^2); 48(b^3)(a^2); 64(a^3)(b^4) is

1) 16(a^4)(b^4) 2) 16 (a^2)(b^2)

2) 2) 16 (a^2)(b^2)

3) 192(a^2)(b^2) 4) 192(a^4)(b^4)

4) 4) 192(a^4)(b^4)​

Answer 1

Answer:

Let the base angle be x

By the condition

\rm{➝~x ~+ ~x~ +~ 40 ~= ~180°}➝ x + x + 40 = 180°

\rm{➝~2x ~+~ 40 ~= ~180°}➝ 2x + 40 = 180°

\rm{➝~2x ~= ~180~ - ~40}➝ 2x = 180 − 40

\rm{➝~2x~ =~ 140}➝ 2x = 140

\rm{➝~x~ = ~{\dfrac{140}{2}}}➝ x =

2

140

\rm{➝~x ~=~ 70}➝ x = 70From the sum of 4 + 3x and 5 - 4x + 2x?, subtract the sum of 3x2 - 5x and -x? + 2x + 5.http://testmoz.com/8306524

Answer 2

Answer:

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Step-by-step explanation:

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