H c f of 210 and 55 is expressible in the form 210×5 -55y, then find y
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HCF (210,55) = 5
thus
5 = 210×5-55y
5= 5(210-11y) (taking 5 common)
1=210-11y (dividing both sides by 5)
-209 = -11
y = 209/11
y = 19
therefore y = 19 is the answer...
hope it helps..
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