Question

h.c.f.of 219,1102and 1218​

Answer 1

Answer :-

HCF (219, 1102, 1218) = 1

Solution :-

First prime factorise 219, 1102, 1218

Prime factorisation of 219

$\begin{array}{r | l} 3 & 219 \\ \cline{1-2} 73 & 73 \\ \cline{1-2} & 1 \end{array}$

Prime factorisation of 1102

$\begin{array}{r | l} 2 & 1102 \\ \cline{1-2} 19 & 551 \\ \cline{1-2} 29 & 29 \\ \cline{1-2} & 1 \end{array}$

Prime factorisation of 1218

$\begin{array}{r | l} 2 & 1218 \\ \cline{1-2} 3 & 609 \\ \cline{1-2} 7 & 203 \\ \cline{1-2} 29 & 29 \\ \cline{1-2} & 1 \\ \end{array}$

219 = 3 * 73 * 1

1102 = 2 * 19 * 29 * 1

1218 = 2 * 3 * 7 * 29 * 1

We know that

HCF = Product the smallest power of each common prime factor of the numbers.

But here we dont have any common prime factor.

So 219, 1102, 1218 are co - primes

HCF of any co - primes is 1

HCF (219, 1102, 1218) = 1

Answer 2

Step-by-step explanation:

Heya Mate

YOUR ANSWER IS 1.

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