H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is 24 x 35 x 52 x 72 . What is the third number?
A) 47628
B) 49874
C) 24157
D) 42146
Answers
Answered by
18
H.C.F of 3240, 3600 and a third number is 36 and their L.C.M is 24 x 35 x 52 x 72 . What is the third number?
A) 47628
B) 49874
C) 24157
D) 42146
Answer: A) 47628
Explanation:
3600=2^4*3^2*5^2
32 40=2^2*3^4*5
H.C.F =36=2^2 *3^2
Since H.C.F is the product of lowest power of common Factor , so the third Number must have (2^2 *3^2) as it`s factor .
Since L.C.M is the Product of Highest power of Common Prime Factor , So the Third number must have 3^5 and 7^2 as it`s factor .Therefore , Third number
=2^2*3^5*7^2
= 4 × 243 × 49
= 47628
A) 47628
B) 49874
C) 24157
D) 42146
Answer: A) 47628
Explanation:
3600=2^4*3^2*5^2
32 40=2^2*3^4*5
H.C.F =36=2^2 *3^2
Since H.C.F is the product of lowest power of common Factor , so the third Number must have (2^2 *3^2) as it`s factor .
Since L.C.M is the Product of Highest power of Common Prime Factor , So the Third number must have 3^5 and 7^2 as it`s factor .Therefore , Third number
=2^2*3^5*7^2
= 4 × 243 × 49
= 47628
Answered by
10
Heyy mate ❤✌✌❤
Here's your Answer...
3600=2^4*3^2*5^2
32 40=2^2*3^4*5
H.C.F =36=2^2 *3^2
Since H.C.F is the product of lowest power of common Factor , so the third Number must have (2^2 *3^2) as it`s factor .
Since L.C.M is the Product of Highest power of Common Prime Factor , So the Third number must have 3^5 and 7^2 as it`s factor .Therefore , Third number
=2^2*3^5*7^2
= 4 × 243 × 49
= 47628
✔✔✔
Here's your Answer...
3600=2^4*3^2*5^2
32 40=2^2*3^4*5
H.C.F =36=2^2 *3^2
Since H.C.F is the product of lowest power of common Factor , so the third Number must have (2^2 *3^2) as it`s factor .
Since L.C.M is the Product of Highest power of Common Prime Factor , So the Third number must have 3^5 and 7^2 as it`s factor .Therefore , Third number
=2^2*3^5*7^2
= 4 × 243 × 49
= 47628
✔✔✔
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