Question

H.C.F OF 5x²y²and 20x³y³ IS:
1) 5x²y²
2) 20x³y²
3)100x^5y³
4)5xy
Please answer i think it's option 4 but i need your opinion!!

Answer 1

Answer:

1

Step-by-step explanation:

from 20 and 5 hcf is5

from x2andx3 it is x2

from y2and y3 it is y2

Therefore 5x2y2

Answer 2

Answer:

Thus HCF=5xy (4) option

Step-by-step explanation:

Let us write prime factors of all 4

1) 5x²y²=5x²y²

2) 20x³y²=5*2*2*x³y²

3)100x^5y³=2*2*5*5x^5y³

4)5xy=5xy

Now let's not down powers common in all 4

5 is common

x is only common

y is commom

Thus ian all foru numbers 5xy is common

Thus HCF=5xy (4) option