Economy, asked by letmedie, 1 year ago

H.C.F of 9269 , 12121 & 20677 is? ​

Answers

Answered by Anonymous
2

Answer:

Hey mate The HCF of 9269,12121,20677 = 713 by Tree method it's solve early hope it helps you

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Answered by NirmalPandya
0

The H.C.F of 9269, 12121 and 20677 is 713.

Given,

Three numbers: 9269, 12121 and 20677.

To Find,

The H.C.F of the given three numbers.

Solution,

the method of finding the H.C.F of the given three numbers is as follows -

We know that H.C.F stands for Highest Common Factor.

So the H.C.F of the three numbers means the highest possible number such that the divides all three numbers and each time the remainder is zero.

Now we will write the prime factorisation of the three numbers.

9269=13^1*23^1*31^1, 12121=17^1*23^1*31^1, and 20677=23^1*29^1*31^1.

So we can observe that the highest common factor in the prime factorisation of all three numbers is 23^1*31^1=713.

So the number 713 is the highest possible number such that after dividing 9269, 12121 and 20677 by 713, the remainder is always zero.

Hence, the H.C.F of 9269, 12121 and 20677 is 713.

#SPJ2

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