Question

H C F of m^3n^3 , 3m^2n and 5 m^2​

Answer 1

Step-by-step explanation:

m^3n^3 = m×m×m×n×n×n

3m^2n = 3×m×m×n×n

5m^2 = 5 × m ×m

Now taking out the common in all three we get,

HCF = m×m = m^2

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