Math, asked by kunalmahtogaganmahto, 5 months ago

H.C.F of two numbers bis 15,then what can be L.C.Mof these number​

Answers

Answered by prabhakardeva
0

Answer:

  • If the HCF of the two numbers is 15 then the two numbers are 15*a and 15*b where 'a' and 'b' are integers. LCM is a least value of the number divisible by both 15*a and 15*b. So if you are expecting to know the smallest value for the LCM then a=1 and b= 2 could be a possible solution.

Step-by-step explanation:

hope it helps you friend

Answered by piyushsharma82paxg79
2

Answer:

If the HCF of the two numbers is 15 then the two numbers are 15*a and 15*b where ‘a’ and ‘b’ are integers.

LCM is a least value of the number divisible by both 15*a and 15*b.

So if you are expecting to know the smallest value for the LCM then a=1 and b= 2 could be a possible solution. This gives the LCM of 15 and 30 as 30.

Here I am assuming the two numbers to be unequal.

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