Question

H.C.F. of two numbers is 6, their L.C.M. is 84 and one of the numbers is 12.
What is the other number?​

Answer 1

Given :-

• HCF of two numbers is 6.
• LCM of two numbers is 84.
• One of the numbers is 12.

To Find :-

• Other number.

Solution :-

Let one number be "R" and other number be "S".

As we know that,

$\sf \red \bigstar \green{LCM × HCF = Product \: of \: two \: numbers}$

✒ .°. LCM × HCF = R × S

[ Putting values ]

➡ 84 × 6 = 12 × S

➡ 504 = 12 × S

➡ S = 504/12

➡ S = 42 $\pink\bigstar$

Hence,

• Other number is 42.

Answer 2

Step-by-step explanation:

let the another no. be x

now,

using the formula

L.C .M × H.C.F = product of the two no.

84 × 6 = 12 × x

504/12 = x

x = 42 ans