Math, asked by niki200626roblox, 6 months ago

H.C.F. of (x^2 - 3x + 2) , (x-1)^4 and (x^2 + 5x - 6) is a)x-1 b) (x-1)^2 c)x+2 d) (x+6)
(no need of explaination)

Answers

Answered by nmchopra
0

Answer:

Answer is option a) x-1

Step-by-step explanation:

x^2 - 3x + 2) = (x-1)(x-2)

(x-1)^4 = (x-1)(x-1)(x-1)(x-1)

x^2 + 5x - 6 =  (x-1)(x+6)

Since only (x-1) is common, it is the HCF

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