Math, asked by zainabgul1353, 3 months ago

H.C.F of (x-2) (x-3) and (x² + x - 6) is ?

Answers

Answered by Anonymous
10

Answer:

(x  - 2)(x - 3) =  {x}^{2}  - 2x - 3x + 6 \\  \\  =  {x}^{2}  - 5x + 6 \\  \\  {x}^{2}  + x - 6 =  {x}^{2}  + 3x - 2x - 6 \\  \\  = x(x + 3) - 2(x + 3) \\  \\  = (x + 3)(x - 2) \\  \\  \\ hcf \: of \: (x - 2)(x - 3) \:  \: and \:  \:  ({x}^{2}  + x - 6) \:  \: is \:  \: { \pink{ (x - 2)}}

Answered by Sankalp050
5

Answer:

H.C.F. of (x-2)(x-3) and (x²+x-6) is (x-2)

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