Question

H.C.F of x2-4 and x²-5x+6 is​

Answer 1

Step-by-step explanation:

x2 - 4 = (x + 2)(x - 2)

x2 - 5x - 6 = x2 - 6x + x - 6

= (x - 6)(x + 1)

x2 + x - 6 = x2 + 3x - 2x - 6

= (x + 3)(x - 2)

Clearly there is no common factor

So H.C.F = 1