Question

H.C.F. of x² + 5x – 6, x^2+ 4x -12,x ^2+ 8x +12​

Answer 1

H.C.F. = x+6

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Answer 2

Given equations;

1.) x² + 5x - 6 -------------------(eq.1)

• x² + 6x - x - 6
• x(x+6) -1(x+6)
• (x - 1)(x + 6) will be its factors

2.)x² + 4x -12 -----------------(eq.2)

• x² + 6x - 2x - 12
• x(x + 6) -2(x + 6)
• (x - 2)(x + 6) will be its factors

3.) x² + 8x + 12. ---------------(eq.3)

• x² + 6x + 2x + 12
• x(x+6)+2(x+6)
• (x+2)(x+6) will be its factors

Thus

eq.1 : (x-1)(x+6)

eq.2 : (x-2)(x+6)

eq.3 : (x+2)(x+6)

Thus the HCF = (x+6)

#answerwithquality

#BAL