Math, asked by lakshman7320, 7 months ago

H.C.FH.C.F  of (x2−3x+2),(x−1)4(x2−3x+2),(x−1)4  and (x2+5x−6)(x2+5x−6)  is​

Answers

Answered by Anonymous
1

Answer:

Hope this will help you

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Step-by-step explanation:

x  

2

−3x+2=x  

2

−2x−x+2

x(x−2)−1(x−2)=(x−2)(x−1)

Now

x  

2

−4x+3=x  

2

−3x−x+3

x(x−3)−1(x−3)=(x−3)(x−1)

Thus, the only common factor is (x-1)

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