H.C.fof 65 and 117 is equal to 65 m- 117 then the
Value of m' is
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0
Answer:2
Explanation:
Answered by
2
Answer:
Hello there !
Euclid's Division Lemma :-
a = bq +r
117 > 65
117 = 65 × 1 + 52 ----> [ 2 ]
65 = 52 x 1 + 13 -----> [1]
52 = 13 x 4 + 0
HCF = 13
13 = 65m + 117n
From [ 1] ,
13 = 65 - 52 x 1
From [2] ,
52 = 117 - 65 x 1 ----> [3]
Hence ,
13 = 65 - [ 117 - 65 x 1 ] ------> from [3]
= 65 x 2 - 117
= 65 x 2 + 117 x [-1 ]
m = 2
n = -1
Explanation:
hope it helps dear.......
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