Question

H+ concentration when 4 gm naoh dissloves in 1000ml water

Answer 1

At first, we have to calculate the [OH] conc. because we already know that the product of conc. of [H] and [OH] is equal to 1 x 10^-14(calculated at standard states).

From the ques., we have

amount of solute = 4 g

molar mass of NaOH = 40 g

Vol. of water = 1000 ml i.e. 1 litre

Now, applying the formula of Molarity for calculating [OH] conc. , we have

[OH] = 4/40 x 1

=0.1 mol/litre

Now,

[H][OH] = 1 x 10^-14

[H] = 1 x 10^-14 / 0.1

=1 x 10^-13 M

this is your answer