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Please answer this problem i will mark u the brainliest if u answer me please it is urgent.....
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Answered by
3
Perimeter of square
=4×side
let side be a
then 4a=16
a=4
Area =a²=4²=16
2. sum of angles of hexagon
=(n-2)×180
(6-2)×180
4×180
=720
=4×side
let side be a
then 4a=16
a=4
Area =a²=4²=16
2. sum of angles of hexagon
=(n-2)×180
(6-2)×180
4×180
=720
Answered by
0
1)
Perimeter of square = 4S = 16 cm
than
4S = 16 Cm
S = 4 Cm
So
Area of square = a^2
(4)^2
16 Cm^2
Option (a) is correct
2)
= (n-2)*180°
= (6-2)*180
= 720°
Where n = number of side
Option (c) 720° is correct answer
Perimeter of square = 4S = 16 cm
than
4S = 16 Cm
S = 4 Cm
So
Area of square = a^2
(4)^2
16 Cm^2
Option (a) is correct
2)
= (n-2)*180°
= (6-2)*180
= 720°
Where n = number of side
Option (c) 720° is correct answer
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