Question

∆H for 302(g) → 203(9) is +272KJ. Then AH for Ag2O() + 03(9) + 2Ag() +202() is (in KJ)
(∆H: (Ag2O) = -32KJ]
(A) -168
(B) +168
(C) -104
(D) +304​

Answer 1

the answer is x

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