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The ten's digit of A two digit number is three times the unit digit.
The sum of the number and the unit digit is 32.
Find the number....
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Let the two numbers be x and y.
If x is the number in the 10th digit and y is the unit digit, then
x = 3y
and 10x+y+y = 32
10x + 2y = 32
and x = 3y.
Substituting the value of x in
10x+2y = 32,
we get
10 * 3y +2y = 32
or 32y = 32 or y = 1
and x = 3.
Thus, the number is 31.
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SOLUTION
Let the two numbers be x & y.
If x is the number in the 10th digit &y is the unit digit, then
x= 3y
=) 10x + y+y = 32
=) 10x+ 2y= 32
Substitute the value of x in 10x+2y= 32
=) 10× 3y + 2y= 32
=) 32y= 32
=) y= 32/32
=) y= 1
& x= 3
Thus the number is 31.
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