Question

H+ , He+ and O ++ are projected in uniform
transverse field with equal velocity. then ratio
of their radii are respectively if their masses are
I a.m.u., 4 a.m.u. and 16 a.in.u. respectively :-
(1) 1:12:22
(2) 2:1:1
(3) 1:2:22
(4) 48

Answer 1

Answer: option 2)2:1:1

Answer 2

If their radii masses are 1a.m.u, 4a.m.u. and 16 a.m.u then the ratio of their radii is 1:2:2

Explanation:

we know that,

                         $r$ ∝ $\frac{\sqrt{m} }{q}$

where,

                      r = Radius

                     m = Mass

                      q = Charge

we have the values of the mass of the particles, putting them in the formula respectively,

∴         $r_{H^{+} }$ : $r_{He^{+} }$ : $r_{o^{++} }$ = $\frac{\sqrt{1} }{1} : \frac{\sqrt{4} }{1} : \frac{\sqrt{16} }{2}$

                                     =$1 :2 :2$

Radius is the smallest for, $H^{+}$ so it is the one that deflected the most in comparison with the other ions.