Question

H.) If (2^3y-1 +10) + 7 = 6 then y =?​

Answer 1

Answer:

$value\: of \: y = \frac{-8}{11}$

Step-by-step explanation:

$(2^{3}y^{-1}+10)+7=6$

$\implies \frac{8}{y}+10=6-7$

$\implies \frac{8}{y}=-1-10=-11$

$\implies \frac{8}{-11}=y$

$\implies y = \frac{-8}{11}$

Therefore,

$value\: of \: y = \frac{-8}{11}$

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Answer 2

The answer is

y = -1

put value of y in given equation..

L.H.S = (2^3y-1+10)+7

= (2^3×-1-1+10)+7

= ( -8-1+10)+7

= (-9+10) +7

= -1+7

L.H.S = 6 = R.H.S