Question

H. If log. (x²+x) - log. (x+1) = 2 then the value of x is​

Answer 1

Step-by-step explanation:

log[(x^2+x)/(x+1)]=2=log 100

so

(x^2+x)/(x+1)=100

or

100x +100=x^2+x

and

99x-x sq+100=0

Tough from here on.