Question

(H) in the adjoining figure ZPQR-90°, Sog QN 1Sog PR
PN-9.NR16 Find QN.
Solution In A PQR ,Seg QN I Sog PR
NO'
Theorem of geometric mean
...fig

NQ ^2=. ......
NO^2.......
=
NQ=12​

Answer 1

Answer:

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