Question

H€LLØ BR@NLY J@NT@
____ ••_____••_____••_____

@n$wer this Qüê$tiøñ:-

•••==========♥===========•••
1. Two concentric circles of radii a and b(a > b) are given. Find the length of the chord of the larger circle which touches the smaller circle.
•••==========♥===========•••

# @n$wer thiß with qü@lïty​

Answer 1

Answer:

Let AB be chord of larger circle which touches smaller circle

So, AB becomes tangent to Smaller circle

As we know ,Perpendicular drawn from centre bisects the chord

So, Draw perpendicular from O to AB

Let foot of perpendicular be D

So, AD =DB

And As AB is tangent to smaller circle

So, OD becomes normal

So, OD = radius of smaller circle = b

OA = radius of larger circle = a

In ∆OAD,

OA^2 = OD^2 + AD^2

AD^2 = OA^2 - OD^2

= a^2 - b^2

AD= √(a^2-b^2)

SO, AB = 2×AD

= 2√(a^2-b^2)

#answerwithquality #BAL