H n - - - n - - - n in hydrogen azide (above) the bond orders of bonds (i) and (ii) are :
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Hey dear,
● Answer -
Bond order of both N-N bonds is 2.
● Explanation -
[Refer to the image for resonant structures of hydrogen azide.]
Bond order is calculated as -
Bond order = (Total no of bonds betn two atoms in all resonating structures) / (Total no of resonating structures)
For 1st bond (HN-N),
Bond order = (2+1+3) / 3
Bond order = 2
For 2nd bond (N-N),
Bond order = (2+3+1) / 3
Bond order = 2
Hence, bond order is 2 for both N-N bonds.
Hope this helps you.
● Answer -
Bond order of both N-N bonds is 2.
● Explanation -
[Refer to the image for resonant structures of hydrogen azide.]
Bond order is calculated as -
Bond order = (Total no of bonds betn two atoms in all resonating structures) / (Total no of resonating structures)
For 1st bond (HN-N),
Bond order = (2+1+3) / 3
Bond order = 2
For 2nd bond (N-N),
Bond order = (2+3+1) / 3
Bond order = 2
Hence, bond order is 2 for both N-N bonds.
Hope this helps you.
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