H,SO, is labelled as 0.98% (w/v) then the molarity of H,SO, solution is
1) 0.1 M
2) 0.2 M
3) 0.25 M
4) 2.5 M
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Answer:
1) 0.1M
Explanation:
0.98%w/v means 0.98gm of solute in 100ml of solution.
%w/v=weight of solute/weight of solution*100
so, Molarity=no.of moles in solute/volume of solution in litre
= given weight/molecular weight/volume of solution in litre
=0.98/98/0.1........(100ml=0.1litre)
=0.01/0.1
=0.1M
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