Question

H. Solve the following numericals.

1. A flask that weighs 345.8 g is filled with 225 ml. of carbon tetrachloride. The weight
of the flask and carbon tetrachloride is found to be 703.55 8. From this information
calculate the density of carbon tetrachloride

7. The density of air is 1.3 kg/m3. What mass of air is contained in a room measuring
2.5 mx 4 m x 10 m?


14. A block is 30 centimeters on each side, and so has a volume of 27,000 cm. It is made of
granite, which has a typical density of 2.8 g/cm3. What is the weight of block?
15. Rohan have to build a box for his scouting project with a volume of 36 cubic centimeters.
The base of the box is 6 cm long and 2 cm wide. How high should he build the box?


pls give the answer only if u know.With proper steps....

pls it is urgent

​

Answer 1

Answer:

1) Density is defined as the mass per unit volume of a substance. So, in this case:

Density = grams / milliliters

We are given the volume (225 mL). However, we must find the mass of just the carbon tetrachloride by subtracting the mass of the flask. This can be done via:

Mass of carbon tetrachloride = (Mass of flask holding carbon tetrachloride) - (Mass of the flask)

Therefore, the mass of the carbon tetrachloride would be:

703.55 - 345.8 = 357.75 grams of carbon tetrachloride

Now we can put the above information into the equation for density:

Again, Density= grams/ milliliters

So:

Density = 357.75 grams / 225 mL = 1.59 grams / milliliter

7) Dimensions of room=4.5 m x 3.5 m x 2.5m

So ,the volume= length x breadth x height

= 4.5 x 3.5 x 2.5

= 39.375 m3

Given that

density of air =1.3 kg m-3

We have a relation:

Mass= denstiy x volume

= 1.3 x 39.375

=51.188 kg

14) Density = mass / volume

mass = density × volume

mass = 27000 × 2.8 = 75600gm or 75.6gm

15)

Given:

The volume of box to be build in the project = 36 cm³

The length of the base of the box = 6 cm

The width of the base of the box = 2 cm

To find:

The height of the box

Solution:

We know that the box to be built in the scouting project will be in the shape of the cuboid.

Therefore, the formula for calculating the volume of a cuboid is given as:

Volume = length × width × height

Now, we will substitute the given values in the formula to get the value of the height of the box

36 = 6 × 2 × height

⇒ 36 = 12 × height

⇒ height = \frac{36}{12}

12

36

⇒ height = 3 cm

Thus, the height of the box to be built in the scouting project will be 3 cm.

Answer 2

Answer:

I hope this answer will help you.