Question

h(t) = 144t – 16t^2. What is the maximum height the ball will reach?

Answer 1

h(t) = 144t-16t2;

For calculating max. value

h'(t) = 0;

so

144-32t = 0;

t = 144/32;

t = 4.5;

Now putting this value in h(t) = 144t-16t2;

we get the maximum value of h(t) is 324