Math, asked by gibsonphasariah, 2 months ago

h(t)=(t+3) 2+5
Over which interval does h have a negative average rate of change?
Choose 1 answer:

(Choice A)
A
-2 t \leq 0−2≤t≤

(Choice B)
B
-4 \leq t \leq -3−4≤t≤−3minus, 4, is less than or equal to, t, is less than or equal to, minus, 3

(Choice C)
C
-3 \leq t \leq 4−3≤t≤4minus, 3, is less than or equal to, t, is less than or equal to, 4

(Choice D)
D
1 \leq t \leq 41≤t≤4

Answers

Answered by Mahesh50124
1

Answer:

Given h(t)=(t+3)² +5 . Rate of change of a function is given by its derivative. Therefore to find rate of change of h(t) , find the derivative of h(t). Therefore h ' (t) is negative for all values of less than -3.

Answered by dhananjaykr2180
0

Step-by-step explanation:

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