H=V^2 SIN^2 TETA/ 2g
check the dimensional consistency
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Given : H = V² sin²θ / 2g
To Find : check the dimensional consistency
Solution:
H = V² sin²θ / 2g
V = Distance / Time
=> V = L / T
V² = L² / T²
sin²θ is dimensionless as sinθ is dimensionless
2 is also dimensionless
g = acceleration
= dv/dt
= L/T.T
= L/T²
H = V² sin²θ / 2g
= (L² / T²)/(L/T²)
= L
Dimension of height = L
Hence dimensional consistency Verified
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