Question

H=v²sin²theta÷2g check dimensional consistency​

Answer 1

Answer:

this is dimensionally consistent.

Please mark my answer as the brainliest.

Explanation:

$(v^2sin^2theta)/2g$

v=m/s

$v^2=m^2/s^2\\sin theta.. is .. dimensionless\\hence.. sin^2theta.. too .. is.. dimensionless..\\g=a=m/s^2\\\\now\\\\v^2/g=(m^2/s^2)/(m/s^2)=m\\hence ..this.. is ..dimensionally ..consistent.$