Question

∆H values for the combustion reaction of ethyl alcohol ,carbon and hydrogen are -330,-94and -68.5 k cal. respectively. Calculate the heat of formation of ethyl alcohol .​

Answer 1

Answer:

Given

C(s)+O

2

(g)⟶CO

2

(g);(ΔH=−393.3kJ)...(i)

S(s)+O

2

(g)⟶SO

2

(g);(ΔH=−293.72kJ)...(ii)

CS

2

(l)+3O

2

(g)⟶CO

2

(g)+SO

2

(g);(ΔH=−1108.76kJ)...(iii)

Mulltiply eq (ii) by 2

S(s)+2O

2

(g)⟶2SO

2

(g);(ΔH=−587.44kJ)...(iv)

Adding eqs. (i) and (iv) and subtracting eq.(iii)

[C(s)+2S(s)+3O

2

(g)−CS

2

(l)−3O

2

(g)→CO

2

(g)+2SO

2

(g)−CO

2

−2SO

2

]

C(s)+2S(s)→CS

2

(l)

This is the required equation

Thus ΔH

f

=−393.3−587.4+1108.76=128.02kJ

Standard Heat of formation of CS

2

(l)=128.02kJ

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