Question

H.W
at 9004, The
Calculate the 7. dissociation
of H₂S is kept
in o. 4 liter
value of ke
for the reaction
2H2319) 22H2(g) + 52 (9)
7. dissociation of H2S(g) if 0.1 mole
vessel
is 104,​

Answer 1

Answer:

2H

2

S(s)⇌2H

2

(g)+S

2

(g)

At equi. (0.1−x) x x/2

Molar conc.

0.4

(0.1−x)

0.4

x

0.8

x

K

c

=

[H

2

S]

2

[H

2

]

2

[S

2

]

=1.0×10

−6

or

0.8(0.1−x)

2

x

3

=1.0×10

−6

as x is very small

0.1−x→0.1

x=2×10

−3

So, percent dissociation=

0.1

2×10

−3

×100=2.0