H=(x:x is a divisor of 18)
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H= { 2, 3, 6, 9, 18 }
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Answer: The set of H contains {1, 2, 3, 6, 9, 18}
Step-by-step explanation:
Since we have given that
H={x:x is a divisor of 18}
i.e. H is the set of all elements which is a divisor of 18 i.e. all those are numbers which can divide 18 completely.
Factor of 18 = 1, 2, 3, 6, 9, 18.
so, H = {1, 2, 3, 6, 9, 18}
Hence, the set of H contains {1, 2, 3, 6, 9, 18}
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