Question

h(x)=x²-3x+5,when x= -5​

Answer 1

Answer:

h(x) =45

solution:-

=x^2 - 3x + 5

=(-5) ^2 -3(-5) + 5

=25 + 15 + 5

= 45

Answer 2

The given question is h(x)=x²-3x+5 when x= -5.

The solution to the given question is we have to find the value of h(x)=x²-3x+5 when the value of x is -5.

The given expression is a quadratic polynomial, where the variables in this expression were raised to the power of 2 and followed by the variable raised to the power of one.

The polynomial is termed for an equation where the power of a variable in an equation is 2 or more than 2.

The answer to the given question is obtained by substitution the value of x in the given expression.

let us substitute the value of x in the question, we get the answer as

${x}^{2} - 3x + 5 \\ {( - 5)}^{2} - 3( - 5) + 5 \\ 25 + 15 + 5 \\ = 25 + 20 \\ = 45$

The value obtained is 45.

Therefore, the final answer to the given question is that h(x)=x²-3x+5 is equal to 45.

h(-5)=45.

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