Question

∆H° and ∆S° for certain reaction are -10KJ and - 44J / K ∆G° is
1) +3112 J, non - spontaneous
2 ) -3112 J, spontaneous
3 ) +31.12 J , non - spontaneous
4) - 31.12J , spontaneous​

Answer 1

Answer:

I don't know because I am not sure

Answer 2

Answer:4

Explanation:When ∆H is negative and T∆S is positive , then the reaction is highly spontaneous with highly negative values of ∆G.

So,4) is the correct answer