H2 + cl2 gives rise to to HCL based on this reaction to prepare 1 mole of HCL the number of moles of cl2 required is
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h2+cl2->2hcl
for one mole of hcl, 1/2 mole of cl2 is required
for one mole of hcl, 1/2 mole of cl2 is required
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- I want solution bro but not direct answer
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