Chemistry, asked by vikasroy7779, 9 months ago

H2(g) + 1/2O2(g) = H20 (l); deltaH = -68.32kcal. Heat of vapourisation of water at 1 atm and 25°C is 10.52kcal. The standard heat of formation of 1mol of water vapour at 25°C is

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Answered by anna775
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ANSWER

Standard molar heat enthalpy (H

) of a compound is equal to its standard heat of formation from most stable states of initial components.

Hence, standard molar enthalpy of formation of CO

2

is equal to the standard molar enthalpy of combustion of carbon (graphite).

C(g)+O

2

(g)→CO

2

(g)

The above reaction can be regarded as the reaction for the combustion of carbon (graphite).

Same reaction can also be regarded as the reaction for the formation of carbon dioxide

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