H2(g)+1/2O2(g) = H2O(l); H= -68.32kcal at 298K heat of vapourisation of water at 1atm and 25C is 10.52kcal. the standard heat of formation( in kcal ) of 1 mole of water vapour at 25C is
(1) 10.52 (2) -78.84 (3) 57.8 (4) -57.8
ans is (4)
Answers
Answer:
vapor is an ideal gas, the internal energy change (ΔU) when 1 mole of water is vaporized at 1 bar pressure and 100∘C (molar enthalpy of vaporization of water at 1 bar and 373 K = 41 kJ/mol and R = 8.314 J/Kmol) will be. (A)4.100kJ/mol(B)3.7904kJ/mol(C)37.904kJ/mol(D)41.00kJ/mol ... H2O(l)→H2O(s).
Explanation:
Some Basic Concepts of Chemistry. 1. 2. 2. States of Matter (Gases and Liquids). 8. 3 ... Nature of Chemical Bond. 29. 6. 9. Hydrogen. 42. 7. 10 s-Block Elements. 47. 8. 12 ..... 13. 1 mole of water = 18 g of water. = 6.022 ×1023 molecules of water. ∴ ...... At 298 K, ∆H is ∆H° i.e., standard heat of formation, ...... 1000K/1atm.
Answer:
(4)
Explanation:
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