H2(g)+Cl2(g) 2Hcl(g) the catalyst in this reactions is
Answers
Answered by
3
Explanation:
Explanation:
H
2
(
g
)
+
C
l
2
(
g
)
→
2
H
C
l
(
g
)
+
Δ
1
H
2
(
g
)
+
C
l
2
(
g
)
→
2
H
C
l
(
l
)
+
Δ
2
The difference between
Δ
1
and
Δ
2
is the process:
2
H
C
l
(
l
)
+
Δ
→
2
H
C
l
(
g
)
Energy is used to boil the liquid.
Δ
2
as written should be larger than
Δ
1
(i.e. when the gas is condensed energy is released).
Note that the fact that exothermic reactions (and this one certainly is) are written as NEGATIVE, is a distractor. Here, because the energy is listed as a product (and not as a separate thermoodynamic property), we should be able to say that
Δ
2
>
Δ
1
. That is we get more energy out when the product is a liquid than when it is a gas.
Others may have a different take on this (and they certainly may have a better way of rationalizing the answer!).
Answered by
7
Answer:
In this reaction no catalyst is used but
4hcl+o2=2cl2+2h2o in this reaction cucl2 is the catalyst
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