Question

. H2 (g) + I2 (g) 2HI (g)Write the relationship between KP and KC for the given reaction.

Answer 1

Answer:- Kp = Kc

Solution:- The given balanced equation is:

$H_2(g)+I_2(g)\leftrightarrow 2HI(g)$

For Kp we use the partial pressures of each gaseous specie and the Kp expression is written as:

$Kp=\frac{(HI)^2}{(H_2)(I_2)}$

The relationship between Kp and Kc is written as:

$Kp=Kc(RT)^\Delta ^n)$

where $\Delta n$ is the moles of gaseous products minus the moles of gaseous reactants.

From balanced equation, we have 2 moles of product and 1 mol of each reactant, It means total 2 moles of the reactants, So:

$\Delta n$ = 2 - 2 = 0

$Kp=Kc(RT)^0)$

Kp = Kc

Hence, for the given reaction, Kp = Kc.

Answer 2

Answer:

kc = kp

Explanation:

kp = kc ( RT )^ng

n=0